Question

Arrange the following saturated solutions in the increasing order of solubilities of the respective solutes.

(a) $125\mathrm{g}$ of solute is present in $625\mathrm{g}$ of solution '$\mathrm{A}$'.

(b) $20\mathrm{g}$ of solute is present in $180\mathrm{g}$ of solution '$\mathrm{B}$'.

(c) $30\mathrm{g}$ of solute is present in $210\mathrm{g}$ of solution '$\mathrm{C}$'.

(d) $15\mathrm{g}$ of solute is present in $120\mathrm{g}$ of solution '$\mathrm{D}$'.

• A. acbd
• B. bdca
• C. cdba
• D. dcab

Answer 1

The correct option is B

bdca

The explanation for the correct option:

A saturated solution is a solution in which the maximum amount of solute is present in a solvent.

As the solute increases in a solvent, the solubility of the solvent decreases.

(a) $125\mathrm{g}$ of solute is present in $625\mathrm{g}$ of solution '$\mathrm{A}$': The amount of solute in the solution is:

$=\frac{125}{625}=\frac{1}{5}$

In solution $\mathrm{A}$, $\frac{1}{5}$part of the solute is present.

(b) $20\mathrm{g}$ of solute is present in $180\mathrm{g}$ of solution '$\mathrm{B}$': The amount of solute in the solution is:

$=\frac{20}{180}=\frac{1}{9}$

In solution $\mathrm{B}$, $\frac{1}{9}$part of the solute is present.

(c) $30\mathrm{g}$ of solute is present in $210\mathrm{g}$ of solution '$\mathrm{C}$': The amount of solute in the solution is:

$=\frac{30}{210}=\frac{1}{7}$

In solution $\mathrm{C}$, $\frac{1}{7}$part of the solute is present.

(d) $15\mathrm{g}$ of solute is present in $120\mathrm{g}$ of solution '$\mathrm{D}$': The amount of solute in the solution is:

$=\frac{15}{120}=\frac{1}{8}$

In solution $\mathrm{D}$, $\frac{1}{8}$part of the solute is present.

The increasing order of solute in the solution is $\frac{1}{9}$ < $\frac{1}{8}$ < $\frac{1}{7}$< $\frac{1}{5}$. So, the order will be bdca.

Therefore, the correct option is (B).