Arrange the following sets of integers in ascending order.
$- 3, 0, - 7, 5, 2$

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Solution

Integer are whole numbers which are in negative direction also. On the right side of zero we have positive integers and on the left side of zero we have negative integers. numbers appearing on the right side on the number line will be greater than the number appearing on the left side.
$- 7$ is smaller than $- 5$ as $- 7$ lies to the left of $- 5$
Hence the given integers in the ascending order are $- 7, - 3, 0, 2, 5$

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When the integers 10, 0, 5, -5, -7 are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.

(a) 0
(b) 5
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When the integers 10, 0, 5, -5, -7 are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.

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(b) 5
(c) -7
(d) -5

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Arrange the following sets of integers in ascending order.-3,0,-7,5,2

Arrange the following sets of integers in ascending order.
$- 3, 0, - 7, 5, 2$