Question

Arrange the following simple pendula in ascending order of their periods of oscillation
a) length 1 m at a place of g = 8 m/s${}^2$
b) of length 2 m at a place of g = 10 m/s${}^2$
c) of length 4m at a place of g= 4m/s${}^2$

• A. a, b, c
• B. b, a, c
• C. b, c, a
• D. c, b, a

Answer 1

The correct option is A a, b, c

$T=2\pi \sqrt{\frac{l}{g}}$
$T_1=2\pi \sqrt{\frac{1}{8}}$
$T_2=2\pi \sqrt{\frac{2}{10}}$
$=2\pi \sqrt{\frac{1}{5}}$
$T_3=2\pi \sqrt{\frac{4}{4}}$
$T_3=2\pi$
$\therefore T_3>T_2>T_1$