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Question

Arrange the following solutions in the decreasing order of pOH
(A) 0.01 M HCl
(B) 0.01 M NaOH
(C) 0.01 M CH3COONa
(D) 0.01 M NaCl

A
(A)>(C)>(D)>(B)
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B
(B)>(D)>(C)>(A)
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C
(B)>(C)>(D)>(A)
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D
(A)>(D)>(C)>(B)
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Solution

The correct option is D (A)>(D)>(C)>(B)
(A) 102M HCl[H+]=102MpH=2pOH=12

(B) 102M NaOH[OH]=102MpOH=2

(C)102M CH3COONa+[OH]>107pOH<7

(D)102M NaClNeutral pOH=7

Decreasing order of pOH,
(A)>(D)>(C)>(B)

Hence, option (d) is correct.

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