Arrange the following substances in order of their increasing volumes at STP.
(i) 1g of CO2; (ii) 1g of Cl2, (iii) 1g of methane CH4 and (iv) 1g of He (Atomic weight of C=12,O=16,H=1,Cl=35.5 and He=4 g/mole)
A
(i), (ii), (iii) and (iv)
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B
(iv), (iii), (ii) and (i)
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C
(ii), (i), (iii) and (iv)
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D
(iv), (ii), (i) and (iii)
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Solution
The correct option is B (ii), (i), (iii) and (iv) Mass is divided with molar mass and multiplied with molar volume (22.4 L at STP) to obtain volume. At STP (i) The volume of 1 g of CO2=1×22.444=0.509 litres
(ii) The volume of 1 g of Cl2=1×22.471=0.315 litres
(iii) The volume of 1 g of CH4=1×22.416=1.4 litres
(iv) The volume of 1 g of He=1×22.44=5.6 litres.
Hence the order of their increasing volume is (ii), (i), (iii), (iv). Note: Volume of a fixed mass of gas is inversely proportional to molecular weight. Higher is the molecular weight of a gas, lower will be the volume.