Arrange the following subtraction statements such that the highest value statement is on the top:
A
14−2
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B
12−12
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C
16−8
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D
20−10
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Solution
14−2=12 12−12=0 16−8=8
We cannot subtract 8 from 6, so we will have to borrow one rod from tens. 20−10=10
The correct order is: 12, 10, 8, 0
i.e. 14−2, 20−10, 16−8, 12−12