Arrange the following three chlorides in decreasing order towards $S_{N^{1}}$ reactivity.

1 > 2 > 3

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2 > 3 > 1

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2 > 1 > 3

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3 > 2 > 1

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Solution

The correct option is B $2 > 3 > 1$
(B) $2 > 3 > 1$
Because of strengths of the ions in following elements
structure given to us.

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_{1}^{1} H,_{1}^{2} H,_{1}^{3} H

Arrange the compounds of each set in order of reactivity towards S_N2 displacement:

(i) 2-Bromo-2-methylbutane, 1-Bromopentane, 2-Bromopentane

(ii) 1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 3-Bromo-2- methylbutane

(iii) 1-Bromobutane, 1-Bromo-2,2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane.

\to

C H_{3} O | | C) O C H C H_{3} 1

C H_{3} O | | C C l 2

C H_{3} O | | C N H C H_{3} 3

C \equiv

B r^{\oplus}

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