Question

Question 88

Arrange the fractions $\frac{6}{7},\frac{7}{8},\frac{4}{5}and\frac{3}{4}$ in descending order.

Answer 1

As per the question

We have to arrange the fractions $\frac{6}{7},\frac{7}{8},\frac{4}{5}$ and $\frac{3}{4}$ in ascending order.

In order to arrange the given fractions in ascending order, we have to first convert them into like fractions, that is fractions having the same denominator.

$\begin{array}{cc}2& 7,8,5,4\\ 2& 7,4,5,2\\ 2& 7,2,5,1\\ 5& 7,1,5,1\\ 7& 7,1,1,1\\ & 1,1,1,1\end{array}$

So, LCM of the denominators, i.e. 7, 8, 5 and 4$=2\times 2\times 2\times 5\times 7=280$

Now, we convert the given fractions to equivalent fractions with denorninator 280.

$\frac{6}{7}=\frac{6\times 40}{7\times 40}=\frac{240}{280},\frac{7}{8}=\frac{7\times 35}{8\times 35}=\frac{245}{280},\frac{4}{5}=\frac{4\times 56}{5\times 56}=\frac{224}{280},\frac{3}{4}=\frac{3\times 70}{4\times 70}=\frac{210}{280}$

245 > 240 > 224 > 210

$\therefore$ $\frac{245}{280}>\frac{240}{280}>\frac{224}{280}>\frac{210}{280}$

$\therefore \frac{7}{8}>\frac{6}{7}>\frac{4}{5}>\frac{3}{4}$