Question

Arrange the fractions $\frac{6}{7},\frac{7}{8},\frac{4}{5}and\frac{3}{4}$ in descending order.

Answer 1

Consider $\frac{6}{7},\frac{7}{8},\frac{4}{5}and\frac{3}{4}$

The LCM of $7,8,5,4$ is $280$

$$\begin{gathered} \frac{\frac{6}{7}\times 280}{280}=\frac{6\times 40}{280}=\frac{240}{280} \\ \frac{\frac{7}{8}\times 280}{280}=\frac{7\times 35}{280}=\frac{245}{280} \\ \frac{\frac{4}{5}\times 280}{280}=\frac{4\times 56}{280}=\frac{224}{280} \\ \frac{\frac{3}{4}\times 280}{280}=\frac{3\times 70}{280}=\frac{210}{280} \end{gathered}$$

The new fraction is $\frac{240}{280},\frac{245}{280},\frac{224}{280},\frac{210}{280}$

Since, $\frac{245}{280}>\frac{240}{280}>\frac{224}{280}>\frac{210}{280}$

Hence, the Descending order is $\frac{245}{280},\frac{240}{280},\frac{224}{280},\frac{210}{280}$