Arrange the fractions given below in order from greatest to least (Descending order)
$\frac{21}{8}, \frac{21}{12}, \frac{21}{20}, \frac{21}{3}$

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Solution

Since, the numerator of given fraction are same
Also
$\frac{21}{8} = 2.6 \frac{21}{12} = 1.7 \frac{21}{20} = 1.05 \frac{21}{3} = 7$
$∴$ The descending order of $\frac{21}{8}, \frac{21}{12}, \frac{21}{20}, \frac{21}{3}$ is $\frac{21}{3}, \frac{21}{8}, \frac{21}{12}, \frac{21}{20}$

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