Arrange the fractions given below in order from greatest to least (Descending order)
$\frac{4}{10}, \frac{1}{2}, \frac{4}{5}, \frac{1}{12}$

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Solution

Since, the denominator of given fraction are not same
consider $\frac{1}{2}, \frac{1}{12}$ , to make numerator equal to other fraction,
if we multiply and divide by $4$ ,we have
$\frac{1}{2} \times \frac{4}{4} = \frac{4}{8} \frac{1}{12} \times \frac{4}{4} = \frac{4}{48}$
Now the given fraction equal to $\frac{4}{10}, \frac{4}{8}, \frac{4}{5}, \frac{4}{48}$
Now the numerator of given fraction are same,
$∴$ The descending order of $\frac{4}{10}, \frac{4}{8}, \frac{4}{5}, \frac{4}{48}$ is $\frac{4}{5}, \frac{4}{8}, \frac{4}{10}, \frac{4}{48}$

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