Question

Arrange the fractions into ascending order $\frac{3}{4},\frac{4}{6},\frac{1}{3},\frac{7}{9}$

Answer 1

Take the LCM of the denominators $4,6,3,9$ i.e. $36$

$\frac{3}{4}=\frac{3\times 9}{4\times 9}=\frac{27}{36},\frac{4}{6}=\frac{4\times 6}{6\times 6}=\frac{24}{36},\frac{1}{3}=\frac{1\times 12}{3\times 12}=\frac{12}{36},\frac{7}{9}=\frac{7\times 4}{9\times 4}=\frac{28}{36}$

Thus the ascending order will be $\frac{1}{3}<\frac{4}{6}<\frac{3}{4}<\frac{7}{9}$