Question

Arrange the given fractions in ascending order:
$\frac{2}{7}$, $\frac{4}{5}$, $\frac{3}{4}$

• A. $\frac{4}{5}$, $\frac{3}{4}$, $\frac{2}{7}$
• B. $\frac{4}{5}$, $\frac{2}{7}$, $\frac{3}{4}$
• C. $\frac{2}{7}$, $\frac{3}{4}$, $\frac{4}{5}$
• D. $\frac{3}{4}$, $\frac{2}{7}$, $\frac{4}{5}$

Answer 1

The correct option is C $\frac{2}{7}$, $\frac{3}{4}$, $\frac{4}{5}$

First, we make all divisors common.
So l.c.m of $7,5,4=140$

Now $\frac{2}{7}\times \frac{20}{20}=\frac{40}{140}$

$\frac{4}{5}\times \frac{28}{28}=\frac{112}{140}$

$\frac{3}{4}\times \frac{35}{35}=\frac{102}{140}$

So the order will be $\frac{2}{7}$, $\frac{3}{4}$, $\frac{4}{5}$