Question

Arrange the given numbers in ascending order.
(Largest number to be placed at the top)

• A. 968
• B. 986
• C. 998
• D. 899
• E. 889

Answer 1

The given numbers have equal number of digits (3).

So, we start by comparing the digits at the hundreds place.
Since $9>8,$ we have 968, 986 and 998 to be greater than 899 and 889.

Now, we compare the digits at the tens place for 968, 986 and 998. Since $6<8<9,$ we have $968<986<998.$

Doing the same for 899 and 889, since $8<9,$ we have $889<899.$

$\therefore 889<899<968<986<998$