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Chlorination

Arrange the h...

Question

Arrange the halogens $F_{2}, C l_{2}, B r_{2}, I_{2},$ in order of their increasing reactivity with alkanes.

I_{2} < B r_{2} < C l_{2} < F_{2}

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B r_{2} < C l_{2} < F_{2} < I_{2}

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F_{2} < C l_{2} < B r_{2} < I_{2}

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B r_{2} < I_{2} < C l_{2} < F_{2}

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Solution

The correct option is A $I_{2} < B r_{2} < C l_{2} < F_{2}$
Since reactivity decreases down the group as the electronegativity of the halogen decreases down the group. Thus, rate of reaction of alkanes with halogens is $I_{2} < {B r}_{2} < {C l}_{2} < F_{2}$ .

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(x^{2} + y^{2})

x

y

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2}, C l_{2}, B r_{2}, I_{2}

F_{2}, C l_{2}, B r_{2}, I_{2}

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