Question

Arrange the isomers of molecular formula $C_4{H}_{9}Cl$ in order of decreasing rate of reaction with sodium iodide in acetone.

• A. $1^{\circ }>2^{\circ }>3^{\circ }$
• B. $2^{\circ }>1^{\circ }>3^{\circ }$
• C. $3^{\circ }>2^{\circ }>1^{\circ }$
• D. None of these

Answer 1

The correct option is A $1^{\circ }>2^{\circ }>3^{\circ }$

Arrange the isomers of molecular formula $C_4{H}_{9}Cl$ in order of The decreasing rate of reaction of the isomers of molecular formula $C_4{H}_{9}Cl$ with sodium iodide in acetone is $1^{\circ }>2^{\circ }>3^{\circ }$ Greater is the number of alkyl groups, greater is teh electron density on carbon attached to Cl and greater is the steric hinderance. Hence, lower is the reactivity.