Question

Arrange the numbers 8695, 8956, 9856 and 9865 in ascending order.

• A. $8695<8956<9865<9856$
• B. $8695<8956<9856<9865$
• C. $8956<8695<9856<9865$
• D. $8695<9856<8956<9865$

Answer 1

The correct option is B $8695<8956<9856<9865$

Since the given numbers have the same number of digits (4), we arrange them based on place values.

$\begin{array}{ccccc}\text{Number}& \text{Thousands}& \text{Hundreds}& \text{Tens}& \text{Ones}\\ 8695& 8& 6& 9& 5\\ 8956& 8& 9& 5& 6\\ 9856& 9& 8& 5& 6\\ 9865& 9& 8& 6& 5\end{array}$

Greater the number of thousands, greater is the number.
$\therefore$9856 and 9865 are both greater than 8695 and 8956.

Comparing the digits at the hundreds place, we have $8\underset{–}{6}95<8\underset{–}{9}56.$

Since the digit in the hundreds place of $9\underset{–}{8}56$ and $9\underset{–}{8}65$ is the same, we compare the digits in the tens place.
$\therefore 98\underset{–}{5}6<98\underset{–}{6}5$

Since $8956<9856,$ we have the correct order as:

$8695<8956<9856<9865$