Question

Arrange the numbers in ascending order $\frac{6}{4},\frac{2}{3},\frac{6}{8},\frac{7}{5},\frac{9}{2}.$

• A. $\frac{2}{3}<\frac{6}{8}<\frac{7}{5}<\frac{6}{4}<\frac{9}{2}$
• B. $\frac{2}{3}<\frac{7}{5}<\frac{6}{4}<\frac{9}{2}<\frac{6}{8}$
• C. $\frac{2}{3}<\frac{6}{4}<\frac{7}{5}<\frac{9}{2}<\frac{6}{8}$
• D. $\frac{6}{4}<\frac{7}{5}<\frac{9}{2}<\frac{6}{8}<\frac{2}{3}$

Answer 1

The correct option is A $\frac{2}{3}<\frac{6}{8}<\frac{7}{5}<\frac{6}{4}<\frac{9}{2}$

L.C.M of number 4, 3,8,5,2 is 960

Equivalent fractions with the denominator 960 are

$\frac{6}{4}\times \frac{240}{240}=\frac{1440}{960}$

$\frac{2}{3}\times \frac{320}{320}=\frac{640}{960}$

$\frac{6}{8}\times \frac{120}{120}=\frac{720}{960}$

$\frac{7}{5}\times \frac{192}{192}=\frac{1344}{960}$

$\frac{9}{2}\times \frac{480}{480}=\frac{4320}{960}$

Ascending order: $\frac{2}{3}<\frac{6}{8}<\frac{7}{5}<\frac{6}{4}<\frac{9}{2}$