Question

Arrange the numbers in descending order $\frac{7}{4},\frac{2}{3},\frac{3}{4},\frac{8}{5},\frac{9}{2}.$

• A. $\frac{9}{2}>\frac{7}{4}>\frac{8}{5}>\frac{2}{3}>\frac{3}{4}$
• B. $\frac{9}{2}>\frac{7}{4}>\frac{8}{5}>\frac{3}{4}>\frac{2}{3}$
• C. $\frac{9}{2}>\frac{8}{5}>\frac{7}{4}>\frac{3}{4}>\frac{2}{3}$
• D. $\frac{9}{2}>\frac{8}{5}>\frac{7}{4}>\frac{2}{3}>\frac{3}{4}$

Answer 1

The correct option is B

$\frac{9}{2}>\frac{7}{4}>\frac{8}{5}>\frac{3}{4}>\frac{2}{3}$

L.C.M of numbers 4, 3, 5, 2 is 60.

Equivalent fractions with denominator 60 are

$\frac{7}{4}\times \frac{15}{15}=\frac{105}{60}$

$\frac{2}{3}\times \frac{20}{20}=\frac{40}{60}$

$\frac{3}{4}\times \frac{15}{15}=\frac{45}{60}$

$\frac{8}{5}\times \frac{12}{12}=\frac{96}{60}$

$\frac{9}{2}\times \frac{30}{30}=\frac{270}{60}$

$\therefore$ The descending order is : $\frac{270}{60}>\frac{105}{60}>\frac{96}{60}>\frac{45}{60}>\frac{40}{60}$

= $\frac{9}{2}>\frac{7}{4}>\frac{8}{5}>\frac{3}{4}>\frac{2}{3}$