Question

Arrange the numbers in each of the following from the smallest to the largest.

$64,15,23,453;2,09,62,000;11,00,83,000;9,53,654$

Answer 1

We have to arrange the numbers from smallest to largest (i.e. in ascending order)

Step I: Comparing the numbers according to their number of digits.

Here, the numbers are not having equal number of digits.

The number $64,15,23,453$ has $9$ digits.

The number $2,09,62,000$ has $8$ digits.

The number $11,00,83,000$ has $9$ digits.

The number $9,53,654$ has $6$ digits.

The number having the least digits is the smallest of all numbers.

Hence, $9,53,654$ is the smallest number.

The second smallest number will be $2,09,62,000$.

So, $9,53,654<2,09,62,000$…………………………..$\left(i\right)$.

Step II: Comparing the left-most digits of the numbers having an equal number of digits.

Now, the remaining two numbers $64,15,23,453;11,00,83,000$ have the same number of digits.

So, we will compare the left-most digit.

The left-most digit is $6$ for the number $64,15,23,453$ and it is $1$ for the number $11,00,83,000$.

As, $1<6$.

So, $11,00,83,000<64,15,23,453$……………$\left(ii\right)$

Also, $2,09,62,000<11,00,83,000$……..$\left(iii\right)$

Step III: Write the ascending order.

From $\left(i\right)$, $\left(ii\right)$ and $\left(iii\right)$,

$9,53,654<2,09,62,000<11,00,83,000<64,15,23,453$.

Therefore, the ascending order (smallest to largest) is $9,53,654;2,09,62,000;11,00,83,000;64,15,23,453$.