Question

Arrange the polygons in the ascending order of sum of internal angles.

• A. Triangle
• B. Rectangle
• C. Pentagon
• D. Hexagon
• E. Septagon

Answer 1

Sum of internal angles of a n sided polygon
= (n-2)$\times {180}^{\circ }$

For a triangle, n=3 $\to$ sum of angles
= (3-2)$\times {180}^{\circ }={180}^{\circ }$

For a Rectangle, n=4 $\to$ sum of angles
= (4-2)$\times {180}^{\circ }={360}^{\circ }$

For a Pentagon, n=5 $\to$ sum of angles
= (5-2)$\times {180}^{\circ }={540}^{\circ }$

For a Hexagon, n=6 $\to$ sum of angles
= (6-2)$\times {180}^{\circ }={720}^{\circ }$

For a Septagon, n=7 $\to$ sum of angles
= (7-2)$\times {180}^{\circ }={900}^{\circ }$