Question

Arrange the rational numbers in ascending order.

$\left(1\right)\frac{-3}{5},\frac{7}{-10},\frac{-5}{6}$

$\left(2\right)\frac{2}{3},\frac{3}{4},\frac{5}{6},\frac{-7}{12}$

Answer 1

$\left(1\right)\frac{-3}{5},\frac{7}{-10},\frac{-5}{6}$ $⟹-\frac{18}{30},-\frac{21}{30},-\frac{25}{30}$

$\therefore$ the ascending order is $\frac{-3}{5},\frac{7}{-10},\frac{-5}{6}$

$\left(2\right)\frac{2}{3},\frac{3}{4},\frac{5}{6},\frac{-7}{12}⟹\frac{8}{12},\frac{9}{12},\frac{10}{12},-\frac{7}{12}$

$\therefore$ the ascending order is $\frac{-7}{12},\frac{2}{3},\frac{3}{4},\frac{5}{6}$