Arrange the reactivity of alcohols in decreasing order for $E_{1}$ elimination reaction.
1. $C H_{3} - H O | C H - C H_{3}$

2. $C H_{3} - H O | C | C H_{3} H - C H_{3}$

3. $C_{6} H_{5} - H O | C | C H_{3} H - C H_{3}$

4. $C H_{3} - C H_{2} - C H_{2} O H$

3, 2, 4, 1

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2, 3, 4, 1

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2, 3, 1, 4

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3, 2, 1, 4

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Solution

The correct option is D
3, 2, 1, 4
$Reactivity α stability of carbocation formed$

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Similar questions

E_{1}

C H_{3} - H O | C H - C H_{3}

C H_{3} - H O | C | C H_{3} H - C H_{3}

C_{6} H_{5} - H O | C | C H_{3} H - C H_{3}

C H_{3} - C H_{2} - C H_{2} O H

C H_{3} - C H = C H - C H_{2} O H P C C - -- \to Product

β

{C H}_{3} {C H}_{2} {C H}_{2} B r (i)

{C H}_{3} - C H {- C H}_{2} B r | {C H}_{3} (i i)

{C H}_{3} - {C H}_{2} - C H - {C H}_{3} | B r (i i i)

H - X

C H_{2} = C H - O H

C H_{2} = C H - C H_{2} O H

C H_{3} - C H_{2} - O H

C H_{3} - C H | O H - C H_{3}

{C H}_{3} - C H = C H - C H O - -- \to H O C l

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