Arrange the set of smaller squares above to form rectangle, find the perimeter and area of rectangle so formed.

P e r i m e t e r = 16 u n i t s a n d A r e a = 7 u n i t s

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P e r i m e t e r = 16 u n i t s a n d A r e a = 7 u n i t^{2}

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P e r i m e t e r = 8 u n i t s a n d A r e a = 7 u n i t^{2}

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P e r i m e t e r = 8 u n i t s a n d A r e a = 7 u n i t s

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Solution

The correct option is B $P e r i m e t e r = 16 u n i t s a n d A r e a = 7 u n i t^{2}$
Given squares can be arranged to form rectangle shown below,

$∴ P e r i m e t e r = 2 (7 + 1) = 16 u n i t s$
$a n d A r e a = 7 \times 1 = 7 u n i t^{2}$

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36 unit squares are joined to form a rectangle with the least perimeter. Perimeter of the rectangle is :

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