Question

Arrange the sides of $△BOC$ in descending order of their lengths. $BO$ and $CO$ are bisectors of angles $ABC$ and $ACB$ respectively.

Answer 1

$\angle ABO={37}^o$

$\angle ACB={180}^o-{117}^o={63}^o$

$\angle OCB=63/2$

$BOC=180-37-31.5=180$

$68.5$

${111.5}^o$

$BC>OC>OB$ (length).