Question

Arrange the values of the following expressions in increasing order from bottom to top.

• A. $2^3÷2^2$
• B. $2^3\times 2^2$
• C. ${\left(2^3\right)}^2$
• D. $2^3\times 3^3$

Answer 1

$2^3\times 2^2=2^5=32$

$2^3÷2^2=2^1=2$

$2^3\times 3^3=(2\times 3{)}^3=6^3=216$

$(2^3{)}^2=2^{3\times 2}=2^6=64$

Hence,
$(2^3\times 3^3)>\left(\right(2^3{)}^2)>(2^3\times 2^2)>(2^3÷2^2)$