Arrange these containers in increasing order of pressure at the base.

$P_{2} > P_{4} > P_{1} > P_{3}$

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P_{2} = P_{4} = P_{1} = P_{3}

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P_{2} > P_{4} > P_{1} = P_{3}

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P_{2} = P_{4} > P_{1} = P_{3}

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Solution

The correct option is D $P_{2} = P_{4} > P_{1} = P_{3}$
Pressure in the container will increases with depth and does not depend on its shape. Hence pressure in container 2 and 4 is same and is greater than that of container 1 and 3.

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