Question

Arrange $x^2{y}^6+x^5{y}^2+x^6{y}^4+3x^2{y}^8$ in descending powers of $x$:

Answer 1

Descending numbers means numbers from highest to lowest.

Now, we have to arrange $x^2{y}^6+x^5{y}^2+x^6{y}^4+3x^2{y}^8$ in descending powers of $x$ that is we have to arrange the powers of $x$ from highest to lowest as shown below:

$x^6{y}^4+x^5{y}^2+x^2{y}^6+3x^2{y}^8$

Hence, the descending order of powers of $x$ is

$x^6{y}^4+x^5{y}^2+x^2{y}^6+3x^2{y}^8$.