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Electrochemical Series

Arrange Zn, P...

Question

Arrange $Z n$ , $P b$ and $A l$ in the decreasing order of their reducing powers under standard conditions.
Given: $E_{Z n^{2 +} | Z n}^{0} = - 0.76 V, E_{P b^{2 +} | P b}^{0} = - 0.13 V$
$E_{A l^{3 +} | A l}^{0} = - 1.66 V$

A

Z n > A l > P b

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B

A 1 > P b > Z n

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C

Z n > A l > P b

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D

A l > Z n > P b

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Solution

The correct option is D $A l > Z n > P b$
Reducing power $\propto \frac{1}{Reduction potential}$
So going by the given numerical values of reduction potential at standard conditions, $A l > Z n > P b$ is the order of reducing power.

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Z n

P b

A l

in the decreasing order of their reducing powers under standard conditions.
Given:

E_{Z n^{2 +} | Z n}^{0} = - 0.76 V, E_{P b^{2 +} | P b}^{0} = - 0.13 V

E_{A l^{3 +} | A l}^{0} = - 1.66 V

Z n

P b

A l

in the increasing order of their reducing powers under standard conditions.
Given:

E_{Z n^{2 +} | Z n}^{0} = - 0.76 V, E_{P b^{2 +} | P b}^{0} = - 0.13 V

E_{A l^{3 +} | A l}^{0} = - 1.66 V

Z n

P b

A l

in the decreasing order of their reducing powers under standard conditions.
Given:

E_{Z n^{2 +} | Z n}^{0} = - 0.76 V, E_{P b^{2 +} | P b}^{0} = - 0.13 V

E_{A l^{3 +} | A l}^{0} = - 1.66 V

Q. (i) Arrange the following metals in an increasing order of their reactivity towards water: Zn, Fe, Mg, Na.
(ii) Arrange the following in increasing order of their oxides to get reduced with carbon: Al, Na, Fe, Cu.
(iii) Arrange the following metals in order of decreasing order of their chemical reactivity: Mg, Ca, Cu, Fe, Na, Zn, Pb.

Q. Arrange the following metals in which they displace each other from the solutions of their salts in decreasing order:

A l, C u, F e, M g

Z n

E_{A l^{3} + / A l}^{0} + - 1.66 V, E_{C u^{2} + / C u}^{0} = + 0.34 V

,

E_{F e^{2} + / F e}^{0} = - 0.44 V, E_{M g^{2} + / M g}^{0} = - 1.40 V

E_{Z n^{2} + / Z n}^{0} = - 0.76 V

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