Arrangement of nuclei in a normal dicot embryo sac is
A
3 + 3 + 2
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B
2 + 4 + 2
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C
3 + 2 + 3
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D
3 + 3 + 3
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Solution
The correct option is C 3 + 2 + 3 In angiosperms (dicots), the polygonum type of embryosac is most common. In this embryosac, the arrangement of the nuclei is 3+2+3, i.e., 3 in antipodal cells, 2 as polar nuclei (which later fuse and form a diploid secondary nucleus) and 3 in egg apparatus (2 in synergids and 1 in egg cell).