Question

Arrangement of nuclei in normal dicot embryo sac is

• A. $3+3+2$
• B. $2+4+2$
• C. $3+2+3$
• D. $2+3+3$

Answer 1

The correct option is C $3+2+3$

A normal dicot embryo sac is a 7-celled but 8-nucleate structure. 3 nuclei are contained in egg apparatus consisting of an egg cell and two synergids, at the micropylar end. 2 nuclei are contained in a large central cell present in the centre of the embryo sac. The rest 3 nuclei are contained in antipodal cells present at the chalazal end.

Hence, the arrangement of nuclei is 3+2+3 ( 3 at micropylar pole, 2 in the centre and 3 at the chalazal pole).

So, the correct answer is C.