Arrangement of two block system is as shown. The net force acting on 1 kg and 2 kg blocks are (assuming the surfaces to be frictionless) respectively.
Fnet=ma N=2(2)=4N
In the figure shown, there is no relative motion between the two blocks. Force of friction acting on 1 kg block is
Three blocks A, B and C of masses 4kg, 2kg and 1kg respectively, are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4kg block, then the contact force between A and B is :