Question

Arrhenius equation maybe represented as:

• A. $ln\frac{A}{k}=\frac{E_a}{RT}$
• B. $\frac{dlnk}{dT}=\frac{E_a}{RT}$
• C. $\log A=\log k+\frac{E_a}{2.303RT}$
• D. $\log (-\frac{E_a}{RT})=\frac{k}{A}$

Answer 1

The correct option is A $ln\frac{A}{k}=\frac{E_a}{RT}$

Arrenhius Equation is given by,

$k=A{e}^{\frac{-E_a}{RT}}$

Therefore, now taking log on both sides

$logk=logA-\frac{E_a}{RT}$

$\frac{E_a}{RT}=ln\frac{A}{k}$