Arun deposited rs- 5000 for 4 years at 61-4- per annum Varun deposited rs- 8000 for 11-2 years at 5

Arun SI = P × R × T100 = 5000100×254× 4 = 1250 A = P + SI 5000 + 1250 = 6250 Varun SI = P × R × T100 = 8000100×32× 5 = 600 A = ...

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Standard VIII

Mathematics

Formula for CI

Arun deposite...

Question

Arun deposited rs. 5000 for 4 years at $6 \frac{1}{4} %$ per annum Varun deposited rs. 8000 for $1 \frac{1}{2}$ years at 5% p.a who gets more amount?

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Solution

Arun
$S I = \frac{P \times R \times T}{100}$
$= \frac{5000}{100} \times \frac{25}{4} \times 4 = 1250$
$A = P + S I$
$5000 + 1250 = 6250$
Varun
$S I = \frac{P \times R \times T}{100}$
$= \frac{8000}{100} \times \frac{3}{2} \times 5 = 600$
$A = P + S I = 8000 + 600 = 8600$

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Arun deposited rs. 5000 for 4 years at 614% per annum Varun deposited rs. 8000 for 112 years at 5% p.a who gets more amount?

ArunSI=P×R×T100=5000100×254×4=1250A=P+SI5000+1250=6250VarunSI=P×R×T100=8000100×32×5=600A=P+SI=8000+600=8600

Arun deposited rs. 5000 for 4 years at $6 \frac{1}{4} %$ per annum Varun deposited rs. 8000 for $1 \frac{1}{2}$ years at 5% p.a who gets more amount?

Arun
$S I = \frac{P \times R \times T}{100}$
$= \frac{5000}{100} \times \frac{25}{4} \times 4 = 1250$
$A = P + S I$
$5000 + 1250 = 6250$
Varun
$S I = \frac{P \times R \times T}{100}$
$= \frac{8000}{100} \times \frac{3}{2} \times 5 = 600$
$A = P + S I = 8000 + 600 = 8600$