Arunoday started walking towards his office at $9 A M$ in the morning. He reached his office at $9 : 30 A M$ . He started walking again to reach home in same time. What is the total distance covered by Arunoday if the average speed of Arunoday is $4 k m / h r$ ?

2 k m

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4 k m

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6 k m

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8 k m

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Solution

The correct option is B $4 k m$
Speed of Arunoday $v = 4 k m / h r$
Time taken to go from home to office $t_{1} = 0.5 h r$
Distance covered in going from home to office $d_{1} = v t_{1} = 4 \times 0.5 = 2 k m$
Time taken to go from office to home $t_{2} = 0.5 h r$
Distance covered in going from office to home $d_{2} = v t_{2} = 4 \times 0.5 = 2 k m$
Thus total distance covered $d = 2 + 2 = 4 k m$

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Arunoday started walking towards his office at 9AM in the morning. He reached his office at 9:30AM. He started walking again to reach home in same time. What is the total distance covered by Arunoday if the average speed of Arunoday is 4km/hr?

Arunoday started walking towards his office at $9 A M$ in the morning. He reached his office at $9 : 30 A M$ . He started walking again to reach home in same time. What is the total distance covered by Arunoday if the average speed of Arunoday is $4 k m / h r$ ?