As $6.00 k g$ of a liquid substance as its freezing point completely freezes, it gives off enough heat to melt $3.00 k g$ of ice at $0^{\circ} C$ . The heat of fusion of the substance is:

2.05 k J / k g

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4.19 k J / k g

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167 k J / k g

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668 k J / k g

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Solution

The correct option is D $167 k J / k g$
Let the latent heat of fusion of the substance be $L k J / k g$ . Then, heat lost by the substance equals the heat gained by ice.
$6 L = 3 \times 333.33$
$L \approx 167$

Hence, latent heat of fusion of the substance is $167 k J / k g$

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As 6.00 kg of a liquid substance as its freezing point completely freezes, it gives off enough heat to melt 3.00 kg of ice at 0∘C. The heat of fusion of the substance is:

The correct option is D 167 kJ/kgLet the latent heat of fusion of the substance be L kJ/kg. Then, heat lost by the substance equals the heat gained by ice.6L=3×333.33L≈167Hence, latent heat of fusion of the substance is 167 kJ/kg

As $6.00 k g$ of a liquid substance as its freezing point completely freezes, it gives off enough heat to melt $3.00 k g$ of ice at $0^{\circ} C$ . The heat of fusion of the substance is:

The correct option is D $167 k J / k g$
Let the latent heat of fusion of the substance be $L k J / k g$ . Then, heat lost by the substance equals the heat gained by ice.
$6 L = 3 \times 333.33$
$L \approx 167$

Hence, latent heat of fusion of the substance is $167 k J / k g$