As a part of a maintenance inspection the compressor of a jet engine is made to spin according to the graph as shown. The number of revolutions made by the compressor during the test is
A
9000
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B
16570
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C
12750
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D
11250
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Solution
The correct option is D 11250 Number of revolution = Area between the graph and time axis = Area of trapezium =12×(2.5+5)×3000=11250 revolution.