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Byju's Answer

Standard XII

Chemistry

Schrodinger Equation

As compared t...

Question

As compared to the $1 s$ electron of $H -$ atom in ground state, which of the following properties appear(s) in the radial probability density of electron of $H -$ atom in first excited state ?

Spherical node appears

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Electron probability density is highest in the vicinity of the nucleus

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Probability density drops to zero after maximum probability is reached

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Probability density rises to second highest value

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Solution

The correct options are
A Spherical node appears
B Electron probability density is highest in the vicinity of the nucleus
C Probability density drops to zero after maximum probability is reached
D Probability density rises to second highest value
For $2 s -$ electrons of $H -$ atom (first excited state),

For $1 s -$ electron of $H -$ atom in ground state,

At point $A, r = a_{0}$
At point $B, r > a_{0}$
$∴$ (a) True (b) True (c) True (d) True

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Similar questions

Q. As compared to the

1 s

electron of

H -

atom in ground state, which of the following properties appear(s) in the radial probability density of electron of

H -

atom in first excited state ?

Question 03

The probability density plots of 1s and 2s orbital are given in figure.

The density of dots in region represents the probability density of finding electrons in the region. On the basis of above diagram which of the following statements is incorrect ?

(a) 1s and 2s orbitals are spherical in shape

(b) The probability of finding electron is maximum near the nucleus

(d) The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases

Q. Which of the following is true ?
a) φ2(r) represent probability density of electron
b) RPF(Radial Probability Function) represent probability of electron in spherical region of unit thickness
c) There is not any radial node in 1s orbital
1) only (a)
2) Both a, b
3) Both b, c
4) a, b ,c

Q. For

1 s

orbital of Hydrogen atom radial wave function is given as:

R (r) = \frac{1}{\sqrt{π}} {(\frac{1}{a_{0}})}^{3 / 2} e^{- r / a_{0}}

where

a_{0} = 0.529 A \circ)

The ratio of radial probability density of finding electron at

r = a_{o}

to the radial probability density of finding electron at the nucleus is given as (x.e

^{- y}

). Calculate the value of (x + y)

Q. Assertion :All

s

-orbital in

H

-atom corresponds to a non-zero probability density at nucleus. Reason: The probability density is given by

: ψ^{2}

and

ψ \propto e^{\frac{- Z r}{2 a_{0}}}

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As compared to the 1s electron of H− atom in ground state, which of the following properties appear(s) in the radial probability density of electron of H− atom in first excited state ?

As compared to the $1 s$ electron of $H -$ atom in ground state, which of the following properties appear(s) in the radial probability density of electron of $H -$ atom in first excited state ?