As depth of immersion of a vertical plane surface increases, the location of centre of pressure
A
comes closer to the centre of gravity of the area
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B
moves apart from the centre of gravity of the area
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C
ultimately coincides with the centre of gravity of the area
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D
remains unaffected
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Solution
The correct option is A comes closer to the centre of gravity of the area The centre of pressure from free surface is hp=hc+IGAhc
where hcis depth of centroid from free surface IGis moment of inertia of vertical plane about horizontal centroidal axis
A is area of the plane
As depth of immersion increases, hc increases and therefore IGAhc decreases. It means that centre of pressure comes closer to centroid.