CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

As depth of immersion of a vertical plane surface increases, the location of centre of pressure

A
comes closer to the centre of gravity of the area
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
moves apart from the centre of gravity of the area
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ultimately coincides with the centre of gravity of the area
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
remains unaffected
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A comes closer to the centre of gravity of the area
The centre of pressure from free surface is
hp =hc+IGAhc
where
hc is depth of centroid from free surface
IG is moment of inertia of vertical plane about horizontal centroidal axis
A is area of the plane
As depth of immersion increases, hc increases and therefore IGAhc decreases. It means that centre of pressure comes closer to centroid.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Centre of Buoyancy
FLUID MECHANICS
Watch in App
Join BYJU'S Learning Program
CrossIcon