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Question

As given in the figure, a series circuit connected across a 200 V, 60 Hz line consists of a capacitor of capacitive reactance 30 Ω, a non-inductive resistor of 44 Ω and a coil of inductive reactance 90 Ω and resistance 36 Ω. The power dissipated in the coil is


​​​​​​​[1 Mark]

A
320 W
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B
176 W
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C
144 W
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D
0 W
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Solution

The correct option is C 144 W

Impedance of the circuit, Z=(R1+R2)2+(XLXC)2

Z=(44+36)2+(9030)2=(80)2+(60)2=100 Ω

Current in the circuit, I=VZ=200 V100 Ω=2 A

Power dissipated in the coil P=I2R2=(2)2×(36)=144 W

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