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Question

# As given in the figure two blocks A & B of weight 20 N and 100 N respectively are in equilibrium. These are being pressed against a wall by force F as shown. If the coefficient of friction between the two blocks is 0.1 and between block B and the wall is 0.15, the frictional force applied by wall on block B is (f2) and the frictional force applied by block B on block A is (f1).

A
f2=120 N
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B
f2=150 N
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C
f1=100 N
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D
f1=20 N
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Solution

## The correct option is D f1=20 NFBD of block A For equilibrium of A f1=WA f1=20 N ...(1) To balance WA force friction will act in upward direction) FBD of block B For equilibrium of B f2=f1+WB f2=20+100 f2=120 N

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