Question

As income is $10\%$ more than that of B. How much per cent is the income of B less than that of A?

Answer 1

Let income of $A$ be $110$.

Let income of $B$ be $100$

So, ($\because$ A's income is $10\%$ more )

So, $\%$ income of $B$ less than that of $A=\frac{110-100}{110}\times 100$

$=\frac{100}{11}=9.09\%$