MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Distance and Displacement

As per Hind...

Question

As per Hindus Mythology, in Mahabharata, the great Warrior BHIMA has capacity to throw Elephants into the space very far away from the surface of Earth. On the surface of Earth, he was able to provide minimum velocity for this purpose, i.e. 11.2 km s-1. (a) What is the name of the velocity provided by BHIMA to throw the elephants? (b) If He had thrown one elephant with the velocity of 20 km s-1, the velocity of the elephant when it had crossed the Gravitational field of Earthwas zero or not?Explain. (c) His one of the enemies also had thrown one horse, did the velocity required for that purpose was less or more than 11.2 kms-1. (d) On Mars, the acceleration of gravity is 1/3 of ‘g’ on Earth and Radius of Mars is 1/3 of Re. What velocity would be required by the BHIMA on Mars to throw one elephant away from its Gravitational field? (e) Calculate the orbital velocity of a satellite, which is revolving around the Earth very close to its surface, using 11.2 km s-1.

Open in App

Solution

Suggest Corrections

thumbs-up

1

Similar questions

Q. A rocket is launched straight up from the surface of the earth. When its altitude is one fourth of the radius of the earth, its fuel runs out and therefore it coasts. The minimum velocity which the rocket must have when it starts to coast if it is to escape from the gravitational pull of the earth is [escape velocity on surface of earth is

11.2 k m / s

]

Q. A rocket is launched normal to the surface of the Earth, away from the Sun, along the line, joining the Sun and the Earth. The Sun is

3 \times 10^{5}

times heavier than the Earth and is at a distance

2.5 \times 10^{4}

times larger than the radius of the Earth. The escape velocity from Earth's gravitational field is

v_{e} = 11.2 k m s^{- 1}

. The minimum initial velocity

(v_{s})

required for the rocket to be able to leave the Sun-Earth system is closest to (Ignore the rotation and revolution of the Earth and the presence of any other planet)

Q. A body is projected upwards with a velocity of

4 \times 11.2 k m / s

from the surface of earth. What will be the velocity of the body when it escapes from the gravitational pull of earth?

Q. The escape velocity on earth is

11.2 k m s^{- 1}

. What is the escape velocity on a planet of radius four times the radius of earth and one fourth of the density of earth?

Q. The escape velocity of a body on the surface of the earth is

11.2 km/s

. If the earth's mass increases to twice its present value and radius of the earth becomes half, the escape velocity from the new surface becomes

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Distance and Displacement

PHYSICS

Watch in App

explore_more_icon

Explore more

Distance and Displacement

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon