As per reaction- N 2g - 20 2g - 2NO 2 g 66 kJ the value of - H r of NO 2 is -

The correct option is A +33kj mol ^ 1 As we know, N _ 2 (g) + #160; 2O _ 2 (g) #160; ⟶ #160; 2NO _ 2 (g) + 66kJ/mole as heat ...

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Standard XII

Chemistry

Hess' Law

As per reacti...

Question

As per reaction, $N_{2}$ (g) + $20_{2}$ (g) $⟶$ ${2 N O}_{2}$ (g) 66 kJ the value of ${Δ H}_{r}$ of ${N O}_{2}$ is :

+33kj

{m o l}^{- 1}

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-33kj

{m o l}^{- 1}

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+66kj

{m o l}^{- 1}

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None of these

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Solution

The correct option is A +33kj ${m o l}^{- 1}$
As we know,
$N_{2}$ (g) + ${2 O}_{2}$ (g) $⟶$ ${2 N O}_{2}$ (g) + $66 k J / m o l e$
as heat of reaction for 2 mole of $N O_{2} = 66 k J / m o l$
so heat of reaction for one mole $= + 33 k J / m o l$

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As per reaction, N2(g) + 202(g) ⟶ 2NO2 (g) 66 kJ the value of ΔHr of NO2 is :

The correct option is A +33kjmol−1As we know,N2(g) + 2O2(g) ⟶ 2NO2 (g) + 66kJ/moleas heat of reaction for 2 mole of NO2=66kJ/molso heat of reaction for one mole =+33kJ/mol

As per reaction, $N_{2}$ (g) + $20_{2}$ (g) $⟶$ ${2 N O}_{2}$ (g) 66 kJ the value of ${Δ H}_{r}$ of ${N O}_{2}$ is :

The correct option is A +33kj ${m o l}^{- 1}$
As we know,
$N_{2}$ (g) + ${2 O}_{2}$ (g) $⟶$ ${2 N O}_{2}$ (g) + $66 k J / m o l e$
as heat of reaction for 2 mole of $N O_{2} = 66 k J / m o l$
so heat of reaction for one mole $= + 33 k J / m o l$