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Question

As per the figure given below, find the total pressure at the bottom.
Density of liquid 1 = 13.6 g/cc
Density of liquid 2 = 5.4 g/cc
Density of liquid 3 = 2.5 g/cc

A
97.35 kPa
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B
123.68 kPa
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C
112.28 kPa
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D
145.68 kPa
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Solution

The correct option is B 123.68 kPa
Pressure at the bottom will be the sum of pressure applied by different layers of the liquid with different densities
height of liquid 3 = h1 = 50 cm = 0.5 m
height of liquid 2 = h2 = 80 cm = 0.8 m
height of liquid 1 = h3 = 60 cm = 0.6 m
ρ1 = 13.6 g/cc = 13600 kg/m3
ρ2 = 5.4 g/cc = 5400 kg/m3
ρ3 = 2.5 g/cc = 2500 kg/m3
So applying formula, P1+P2+P3 = Total Pressure P
P = 13600×g×0.5+5400×g×0.8+2500×g×0.6
P = 123676 Pa = 123.68 kPa

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