    Question

# As per the figure given below, find the total pressure at the bottom. Density of liquid 1 = 13.6 g/cc Density of liquid 2 = 5.4 g/cc Density of liquid 3 = 2.5 g/cc A
97.35 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
123.68 kPa
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
112.28 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
145.68 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 123.68 kPaPressure at the bottom will be the sum of pressure applied by different layers of the liquid with different densities height of liquid 3 = h1 = 50 cm = 0.5 m height of liquid 2 = h2 = 80 cm = 0.8 m height of liquid 1 = h3 = 60 cm = 0.6 m ρ1 = 13.6 g/cc = 13600 kg/m3 ρ2 = 5.4 g/cc = 5400 kg/m3 ρ3 = 2.5 g/cc = 2500 kg/m3 So applying formula, P1+P2+P3 = Total Pressure P P = 13600×g×0.5+5400×g×0.8+2500×g×0.6 P = 123676 Pa = 123.68 kPa  Suggest Corrections  1      Similar questions  Explore more