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Question

As shown in Fig, a dust particle with mass m=5.0×109kg and charge q0= 2.0 n C starts from rest at point a and moves in a straight line to point b. What is its speed v at point b?
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A
26 ms1
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B
34 ms1
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C
46 m s1
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D
14 m s1
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Solution

The correct option is C 46 m s1
There is no external force so apply conservation of mechanical energy between points a and b
initially particle is at rest so kinetic energy at point a is zero
(KE+PE)a=(KE+PE)b
0+k(3×109)q00.01k(3×109)q00.02=12mv2+k(3×109)q00.02k(3×109)qo0.01
Put the values and get v=1215=46ms1

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