As shown in figure, a charge +2C is situated at the origin O and another charge +5C is on the x-axis at the point A. Later the charge from the point A is brought to a point B on the y-axis. The work done is: (given 14πε0=9×109m/F)
A
45×109J
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B
90×109J
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C
zero
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D
−45×109J
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Solution
The correct option is D zero Work done =Uf−Ui =14πε0×2×5(12−12)=0