As shown in figure, a particle starts to move from A to B and then finally stops at point C. Total displacement and distance covered by particle during its journey from A to C via B is (in m):
A
−3,7
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B
3,3
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C
−3,3
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D
3,7
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Solution
The correct option is A−3,7 Initial position of particle, xA=1m
Final position of particle is, xC=−2m
Displacement, Δx=xC−xA =−2−1=−3m
Note, here −ve direction implies that displacement is from 𝐴 to 𝐶 towards left.Distance, S=|AB|+|BC| =|3−1|+|(−2)−3| =|2|+|−5| =2+5=7