You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equation of Continuity

As shown in f...

Question

As shown in figure, at the mouth of the tap the area of cross-section is 2.5 $c m^{2}$ and the speed of water is 3 m/s. The area of cross-section of the water column 80 cm below the tap is

2cm²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5cm²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1cm²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

.5cm²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
1.5cm²

$A_{1} = 2.5 c m^{2}, v_{1} = 3 m / s, h = 0.8 m, g = 10 m / s^{2}$

$v_{2}^{2} = v_{1}^{2} + 2 g h = 25 o r v_{2} = 5 m / s$

$A_{1} v_{1} = A_{2} v_{2} o r A_{2} = \frac{A_{1} v_{1}}{v_{2}} = 1.5 c m^{2}$

Suggest Corrections

Similar questions

2.0 c m^{2}

3 m / s

80 c m

(u s e g = 10 m / s^{2})

c m^{2}

1 m/s

10^{- 4} m^{2}

0.15 m

h = 0.2 m

\sqrt{2} \times 10^{- 4} m^{2}

0.2 m

[Assume g = 10 {m/s}^{2}]

1.0 m s^{- 1}

10 c m^{2}

0.15 m

Join BYJU'S Learning Program